How will the number -8’d4 (in Verilog) be internally represented as bits?

In Verilog, -8'd4 represents a negative 8-bit decimal number. Here's how it's represented in bits:

1. First, represent the absolute value of -4 in 8-bit binary form. 4 in binary is 100, so in 8-bit form, it's 00000100.

2. Next, find the 2's complement of the binary number to represent the negative value. To do this, first find the 1's complement (flip all the bits), which gives 11111011.

3. Then, add 1 to the 1's complement to get the 2's complement. 11111011 + 1 = 11111100.

So, -8'd4 in Verilog is represented as 11111100 in bits.