If a truck travelled 300 km at 90 km/h and then returned at 65 km/h, what was the average speed for the journey, correct to one decimal place?
Question
If a truck travelled 300 km at 90 km/h and then returned at 65 km/h, what was the average speed for the journey, correct to one decimal place?
Solution
Step 1: Calculate the time taken for each leg of the journey.
For the first leg of the journey, the truck traveled 300 km at 90 km/h. So, the time taken is distance/speed = 300 km / 90 km/h = 3.33 hours.
For the return journey, the truck traveled the same distance at a slower speed of 65 km/h. So, the time taken is distance/speed = 300 km / 65 km/h = 4.62 hours.
Step 2: Calculate the total time taken for the journey.
The total time taken for the journey is the sum of the time taken for each leg. So, total time = 3.33 hours + 4.62 hours = 7.95 hours.
Step 3: Calculate the total distance traveled.
The truck traveled 300 km each way, so the total distance traveled is 2 * 300 km = 600 km.
Step 4: Calculate the average speed.
The average speed is the total distance traveled divided by the total time taken. So, average speed = total distance / total time = 600 km / 7.95 hours = 75.5 km/h.
So, the average speed for the journey, correct to one decimal place, is 75.5 km/h.
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