Write the first six terms of the sequence.$a_n=3n-1$an=3n−1The first six terms of the sequence are , , , , ,

Question

Write the first six terms of the sequence. $a_n=3n-1$ an=3n−1The first six terms of the sequence are , , , , ,

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the first six terms of the sequence $a_n=3n-1$ , we substitute the values of n from 1 to 6 into the formula.

For n=1, $a_1=3(1)-1=2$

For n=2, $a_2=3(2)-1=5$

For n=3, $a_3=3(3)-1=8$

For n=4, $a_4=3(4)-1=11$

For n=5, $a_5=3(5)-1=14$

For n=6, $a_6=3(6)-1=17$

So, the first six terms of the sequence are 2, 5, 8, 11, 14, 17.

Similar Questions

Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = 6n2 + 9n − 6

Find the first five terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = 4(3)n

Write the first six terms of the sequence.$a_n=5^{n-1}$an=5n−1, , ,

Write the first five terms of the sequence defined recursively.a1 = 13, ak + 1 = (−2)aka1 = a2 = a3 = a4 = a5 = Use the pattern to write the nth term of the sequence as a function of n. (Assume that n begins with 1.)an =

The nth term of a sequence is given as 2n3−12 . Find the 14th and 17th terms of thesequence

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.