A man of weight 80 kg is standing in an elevator which is moving with an acceleration of 6 m/s2 in upward direction. The apparent weight of the man will be (g = 10 m/s2).A 1480 N B 1280 N C 1380 N D 2520 N

To find the apparent weight of the man in the elevator, we need to consider the effect of the acceleration on his weight.

1. First, we need to calculate the net force acting on the man. This can be done using Newton's second law, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the man is 80 kg and the acceleration of the elevator is 6 m/s^2.

   F = m * a F = 80 kg * 6 m/s^2 F = 480 N

2. The apparent weight of the man is equal to the net force acting on him. Therefore, the apparent weight of the man is 480 N.

3. However, we need to consider the effect of gravity on the man as well. The weight of an object is given by the formula weight (W) = mass (m) multiplied by the acceleration due to gravity (g). In this case, the acceleration due to gravity is 10 m/s^2.

   W = m * g W = 80 kg * 10 m/s^2 W = 800 N

4. The apparent weight of the man is the difference between the net force acting on him and his weight due to gravity.

   Apparent weight = Net force - Weight due to gravity Apparent weight = 480 N - 800 N Apparent weight = -320 N

5. The negative sign indicates that the apparent weight is in the opposite direction to the force of gravity. In this case, the elevator is moving upward, so the apparent weight of the man is in the downward direction.

Therefore, the apparent weight of the man in the elevator is -320 N.