13.5g of liquid helium at its boiling point of −269 ∘ C, is heated until it is all boiled away. If the specific latent heat of vaporisation of helium is 21.1kJ/kg, how much energy is needed?Answer in kJ and assume no temperature change occurs as a result of this heat transfer.
Question
13.5g of liquid helium at its boiling point of −269 ∘ C, is heated until it is all boiled away. If the specific latent heat of vaporisation of helium is 21.1kJ/kg, how much energy is needed?Answer in kJ and assume no temperature change occurs as a result of this heat transfer.
Solution
First, we need to convert the mass of helium from grams to kilograms because the specific latent heat of vaporisation is given in kJ/kg.
1 kg = 1000 g, so 13.5 g = 13.5/1000 = 0.0135 kg.
The energy (Q) needed to change the phase of a substance can be calculated using the formula:
Q = m * L
where: m is the mass of the substance, L is the specific latent heat of the substance.
Substituting the given values into the formula, we get:
Q = 0.0135 kg * 21.1 kJ/kg = 0.28485 kJ
So, approximately 0.285 kJ of energy is needed to boil away all the liquid helium.
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