To solve the quadratic equation 5q^2 + 21q + 4 = 0, we can use the quadratic formula, which is given by:

q = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 5, b = 21, and c = 4.

Step 1: Calculate the discriminant (b^2 - 4ac)
Discriminant = (21)^2 - 4*5*4 = 441 - 80 = 361

Step 2: Substitute a, b, and the discriminant into the quadratic formula
q = [-21 ± sqrt(361)] / (2*5)
q = [-21 ± 19] / 10

Step 3: Solve for q
q = [-21 + 19] / 10 = -2/10 = -0.2
q = [-21 - 19] / 10 = -40/10 = -4

So, the solutions to the equation 5q^2 + 21q + 4 = 0 are q = -0.2 and q = -4.

Question

To solve the quadratic equation 5q^2 + 21q + 4 = 0, we can use the quadratic formula, which is given by:

q = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 5, b = 21, and c = 4.

Step 1: Calculate the discriminant (b^2 - 4ac)
Discriminant = (21)^2 - 4*5*4 = 441 - 80 = 361

Step 2: Substitute a, b, and the discriminant into the quadratic formula
q = [-21 ± sqrt(361)] / (2*5)
q = [-21 ± 19] / 10

Step 3: Solve for q
q = [-21 + 19] / 10 = -2/10 = -0.2
q = [-21 - 19] / 10 = -40/10 = -4

So, the solutions to the equation 5q^2 + 21q + 4 = 0 are q = -0.2 and q = -4.

Knowee AI · Accepted Answer

To solve the quadratic equation 5q^2 + 21q + 4 = 0, we can use the quadratic formula, which is given by:

q = [-b ± sqrt(b^2 - 4ac)] / (2a)

Here, a = 5, b = 21, and c = 4.

Step 1: Calculate the discriminant (b^2 - 4ac)
Discriminant = (21)^2 - 4*5*4 = 441 - 80 = 361

Step 2: Substitute a, b, and the discriminant into the quadratic formula
q = [-21 ± sqrt(361)] / (2*5)
q = [-21 ± 19] / 10

Step 3: Solve for q
q = [-21 + 19] / 10 = -2/10 = -0.2
q = [-21 - 19] / 10 = -40/10 = -4

So, the solutions to the equation 5q^2 + 21q + 4 = 0 are q = -0.2 and q = -4.

Solve the equation 5q2+21q+4=0.