Water flows through a 1000 cm^2 pipe at 200 kg/s. Find the velocity, if the water is at 20 bar and 45 ℃.1 point2.0 m/s0.0002 m/s0.55 m/s5.5 m/s6.Question 6Consider a pump with a mass flow rate of wat

The question seems to be incomplete, but I can help you find the velocity of the water in the pipe with the given information.

First, we need to understand that the velocity of a fluid (in this case, water) flowing through a pipe can be calculated using the formula:

v = Q/A

where: v = velocity (m/s) Q = flow rate (m^3/s) A = cross-sectional area of the pipe (m^2)

In this case, we are given the mass flow rate (200 kg/s), not the volumetric flow rate. However, we can convert mass flow rate to volumetric flow rate using the formula:

Q = m/ρ

where: m = mass flow rate (kg/s) ρ = density of the fluid (kg/m^3)

The density of water at 45 ℃ is approximately 990 kg/m^3. So, we can calculate Q as follows:

Q = 200 kg/s / 990 kg/m^3 = 0.202 m^3/s

The cross-sectional area of the pipe is given as 1000 cm^2. We need to convert this to m^2 by dividing by 10,000 (since 1 m^2 = 10,000 cm^2):

A = 1000 cm^2 / 10,000 = 0.1 m^2

Now we can calculate the velocity:

v = Q/A = 0.202 m^3/s / 0.1 m^2 = 2.02 m/s

So, the velocity of the water in the pipe is approximately 2.02 m/s.