Let's denote the speed of the boat in still water as 'b' and the speed of the current as 'c'. Given that the ratio of the speed of the boat to the speed of the current is 4:3, we can write:

b/c = 4/3
= b = 4c/3 ----(1)

The speed of the boat while going upstream (against the current) is (b-c) and while going downstream (with the current) is (b+c).

The problem states that the difference between the distance covered by the boat in 3 hours upstream and in 3 hours downstream is 54 km. We know that distance = speed * time, so we can write:

3(b+c) - 3(b-c) = 54
= 3b + 3c - 3b + 3c = 54
= 6c = 54
= c = 54/6
= c = 9 km/hr

Substituting c = 9 km/hr in equation (1) we get:

b = 4*9/3
= b = 12 km/hr

So, the speed of the boat in still water is 12 km/hr.

Question

Let's denote the speed of the boat in still water as 'b' and the speed of the current as 'c'. Given that the ratio of the speed of the boat to the speed of the current is 4:3, we can write:

b/c = 4/3
=> b = 4c/3 ----(1)

The speed of the boat while going upstream (against the current) is (b-c) and while going downstream (with the current) is (b+c).

The problem states that the difference between the distance covered by the boat in 3 hours upstream and in 3 hours downstream is 54 km. We know that distance = speed * time, so we can write:

3(b+c) - 3(b-c) = 54
=> 3b + 3c - 3b + 3c = 54
=> 6c = 54
=> c = 54/6
=> c = 9 km/hr

Substituting c = 9 km/hr in equation (1) we get:

b = 4*9/3
=> b = 12 km/hr

So, the speed of the boat in still water is 12 km/hr.

Knowee AI · Accepted Answer

Let's denote the speed of the boat in still water as 'b' and the speed of the current as 'c'. Given that the ratio of the speed of the boat to the speed of the current is 4:3, we can write:

b/c = 4/3
=> b = 4c/3 ----(1)

The speed of the boat while going upstream (against the current) is (b-c) and while going downstream (with the current) is (b+c).

The problem states that the difference between the distance covered by the boat in 3 hours upstream and in 3 hours downstream is 54 km. We know that distance = speed * time, so we can write:

3(b+c) - 3(b-c) = 54
=> 3b + 3c - 3b + 3c = 54
=> 6c = 54
=> c = 54/6
=> c = 9 km/hr

Substituting c = 9 km/hr in equation (1) we get:

b = 4*9/3
=> b = 12 km/hr

So, the speed of the boat in still water is 12 km/hr.

The speed of a boat in still water and the speed of the current is in a ratio of 4 : 3. If the difference between the distance covered by the boat in 3 hours upstream and in 3 hours downstream is 54 km. The speed of a boat in still water is

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