There are n teams numbered from 0 to n - 1 in a tournament.Given a 0-indexed 2D boolean matrix grid of size n * n. For all i, j that 0 <= i, j <= n - 1 and i != j team i is stronger than team j if grid[i][j] == 1, otherwise, team j is stronger than team i.Team a will be the champion of the tournament if there is no team b that is stronger than team a.Return the team that will be the champion of the tournament.
Question
There are n teams numbered from 0 to n - 1 in a tournament.Given a 0-indexed 2D boolean matrix grid of size n * n. For all i, j that 0 <= i, j <= n - 1 and i != j team i is stronger than team j if grid[i][j] == 1, otherwise, team j is stronger than team i.Team a will be the champion of the tournament if there is no team b that is stronger than team a.Return the team that will be the champion of the tournament.
Solution
The problem can be solved by following these steps:
-
Initialize a variable
championto 0. This variable will keep track of the current strongest team. -
Iterate over the range from 1 to n. For each iteration, check if the current team is stronger than the current champion. This can be done by checking if
grid[champion][i]is 0 (which means team i is stronger than the current champion). If it is, updatechampionto be the current team. -
After the loop,
championwill be the team that is stronger than all other teams, so returnchampion.
Here is a Python code snippet that implements these steps:
def tournamentChampion(grid):
n = len(grid)
champion = 0
for i in range(1, n):
if grid[champion][i] == 0:
champion = i
return champion
This function works by initially assuming that team 0 is the champion, and then iteratively checking if there is a team that is stronger than the current champion. If such a team is found, it becomes the new champion. After checking all teams, the function returns the champion.
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