A pitot-static tube is used to measure air velocity. If a manometer connected to theinstrument indicates a difference in pressure head between the tappings of 5mm of water.calculate the air velocity assuming the coefficient of the pitot tube to be 0.98. Density of air= 1.2Kg/m^3.
Question
A pitot-static tube is used to measure air velocity. If a manometer connected to theinstrument indicates a difference in pressure head between the tappings of 5mm of water.calculate the air velocity assuming the coefficient of the pitot tube to be 0.98. Density of air= 1.2Kg/m^3.
Solution
To calculate the air velocity, we can use the Bernoulli's equation which is given by:
V = sqrt((2*(ΔP))/ρ)
Where: V = velocity ΔP = difference in pressure ρ = density of the fluid
Given: ΔP = 5 mm of water = 5 * 9.81 * 10^-3 N/m^2 (since 1 mm of water = 9.81 * 10^-3 N/m^2) ρ = 1.2 kg/m^3 Coefficient of the pitot tube = 0.98
Substituting the given values into the equation, we get:
V = sqrt((2*(5 * 9.81 * 10^-3))/1.2)
After calculating the above expression, we get the velocity. However, since we are given a coefficient of the pitot tube, we need to multiply the calculated velocity by this coefficient to get the actual velocity.
So, the actual velocity V_actual = V * 0.98
This will give you the air velocity.
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