A pilot-static tube is used to measure air velocity. If a manometer connected to the instrument indicates a difference in pressure head Between the tappings of 4mm of water, calculate the air velocity assuming the coefficient of the pilot tube to be unity. Density of air 4.2KG/M²

To calculate the air velocity, we can use Bernoulli's equation which is applied in fluid dynamics. The equation is:

V = sqrt(2 * ΔP / ρ)

Where: V = velocity ΔP = pressure difference ρ = density of the fluid

Given: ΔP = 4 mm of water = 4 * 9.81 * 10^-3 N/m² (since 1 mm of water is approximately 9.81 * 10^-3 N/m²) ρ = 4.2 kg/m³

Substituting the given values into the equation:

V = sqrt(2 * 4 * 9.81 * 10^-3 / 4.2) V = sqrt(0.018648 / 4.2) V = sqrt(0.00444) V = 0.0667 m/s

So, the air velocity is approximately 0.0667 m/s.

To calculate the air velocity, we can use Bernoulli's equation which in this case simplifies to the Pitot tube formula:

V = sqrt(2 * ΔP / ρ)

Where: V is the velocity, ΔP is the pressure difference, and ρ is the density of the fluid (air in this case).

Given: ΔP = 4 mm of water = 4 * 9.81 * 10^-3 N/m² (since 1 mm of water is approximately 9.81 * 10^-3 N/m²), ρ = 4.2 kg/m³.

Substituting these values into the formula, we get:

V = sqrt(2 * 4 * 9.81 * 10^-3 / 4.2) V = sqrt(0.018648 / 4.2) V = sqrt(0.00444) V = 0.0667 m/s.

So, the air velocity is approximately 0.0667 m/s.

To calculate the air velocity, we can use Bernoulli's equation which in this case simplifies to the Pitot tube formula:

V = sqrt(2 * ΔP / ρ)

Where: V is the velocity, ΔP is the pressure difference, and ρ is the density of the fluid.

Given: ΔP = 4 mm of water = 4 * 9.81 * 10^-3 N/m² (since 1 mm of water is approximately 9.81 * 10^-3 N/m²), ρ = 4.2 kg/m³.

Substituting these values into the formula, we get:

V = sqrt(2 * 4 * 9.81 * 10^-3 / 4.2) V = sqrt(0.07848 / 4.2) V = sqrt(0.0186857143) V = 0.1367 m/s.

So, the air velocity is approximately 0.137 m/s.