An object weighs 10N in air. When immersed fully in water, it weighs only 8N. The weight of the liquid displaced by the object in standard units will be
Question
An object weighs 10N in air. When immersed fully in water, it weighs only 8N. The weight of the liquid displaced by the object in standard units will be
Solution
The weight of the liquid displaced by the object can be calculated using Archimedes' principle, which states that the buoyant force on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.
In this case, the object weighs 10N in air and 8N in water. The difference in weight is due to the buoyant force exerted by the water on the object.
So, the weight of the water displaced by the object is equal to the difference in weight of the object in air and in water.
Weight of water displaced = Weight in air - Weight in water = 10N - 8N = 2N
Therefore, the weight of the water displaced by the object is 2N.
Similar Questions
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be ‘x’ N. Find the value of ‘x’.
A 10 kg ball weighs 98 N in air and weighs 75 N when submerged in water. The upward buoyant force on the ball is
What is the weight of the body when fully immersed in water
The buoyant force acting on an object immersed in a fluid is equal to:2 marksThe weight of the objectThe volume of the objectThe volume of the displaced fluidThe density of the object
f the weight of an object is < the Buoyant Force, the object will ......................ASinkBRiseCRemain at the same level
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.