An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be ‘x’ N. Find the value of ‘x’.
Question
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be ‘x’ N. Find the value of ‘x’.
Solution
The weight of the object in air is given as 10 N. When the object is fully immersed in water, its weight is 8 N. The difference in weight is due to the buoyant force exerted by the water, which is equal to the weight of the water displaced by the object.
So, to find the weight of the liquid displaced by the object, we subtract the weight of the object in water from its weight in air.
Mathematically, this can be represented as:
Weight of the liquid displaced = Weight in air - Weight in water
Substituting the given values:
Weight of the liquid displaced = 10 N - 8 N = 2 N
So, the weight of the liquid displaced by the object, 'x', is 2 N.
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