Finally, find Q3.Recall that the third quartile, Q3, is the median of the upper half of the data. That is, the median of the data located above the Q2 position.Consider the ordered list of data values. The median, Q2, which has been determined, has been underlined for clarity.3,   6,   6,   7,   8,   8,   9,   10,   11There are nine values in the whole data set, but there are only values to the right of the underlined median. The third quartile, Q3, will be equal to the median of these values.Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values.median = sum of middle two values2The middle two values of the upper half are 9 and .Now, calculate the third quartile, Q3.Q3  =  9 + 2  =  2  =

The question seems to be incomplete as it does not provide all the necessary information to calculate Q3. Specifically, the second middle value of the upper half of the data set is missing.

However, I can explain the steps to find Q3 given a complete data set:

1. Arrange the data in increasing order.
2. Find the median (Q2). If the data set has an odd number of observations, the median is the middle value. If the data set has an even number of observations, the median is the average of the two middle values.
3. Divide the data set into two halves: one half below the median and one half above the median.
4. Find the median of the upper half of the data. This is Q3.

In the given data set, the values to the right of the median are 8, 9, 10, and 11. But we are missing one value. If we had that value, we would find the median of this upper half to get Q3. If the upper half has an odd number of observations, Q3 is the middle value. If the upper half has an even number of observations, Q3 is the average of the two middle values.