Now, find the median.Recall that the median is the central value of an ordered distribution. Note that the median is also the second quartile, Q2.For an number of data values, as we have here, the median is the middle data value of the ordered data set.The median of the ordered data set 3   6   6   7   8   8   9   10   11 is .

Next, find Q1.Recall that the first quartile, Q1, is the median of the lower half of the data. That is, the median of the data located below the Q2 position.Consider the ordered list of data values. The median, Q2, which was determined in the last step, has been underlined for clarity.3,   6,   6,   7,   8,   8,   9,   10,   11There are nine values in the whole data set, but there are only values to the left of the underlined median. The first quartile, Q1, will be equal to the median of these values.Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values.median = sum of middle two values2The middle two values of the lower half of the data set are 6 and .Now, calculate the first quartile. Q1.Q1  =  6 + 2  =  2  =

In the data set below, what are the lower quartile, the median, and the upper quartile?2345577779lower quartile = median = upper quartile =

Consider the following data set: 5, 6, 7, 7, 8, 9. What is the median of the data set?a.6b.7c.7.5d.8

The median of the following data is: 1, 7, 9, 3, 4, 5, 6

Given the data set 8, 10 , 7 , 2 , 6 , 9 , 3 , 8 , 9. What is the median?8657