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A plane wave E =50 sin (ωt-5x) ay V/m in lossless medium (ε=ε0, µ=5µ0) encounters a lossy medium (ε=4ε0, µ=µ0,σ=0.1 S/m) normal to the x-axis at x=0. Examine i) Reflection coefficient (Γ) and VSWR(S) ii) Total electric and magnetic field intensity(E,H)

Question

A plane wave E =50 sin (ωt-5x) ay V/m in lossless medium (ε=ε0, µ=5µ0) encounters a lossy medium (ε=4ε0, µ=µ0,σ=0.1 S/m) normal to the x-axis at x=0. Examine i) Reflection coefficient (Γ) and VSWR(S) ii) Total electric and magnetic field intensity(E,H)

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Solution

This problem involves the study of electromagnetic waves, specifically plane waves, and their interaction with different media. We'll solve it in two parts as requested.

i) Reflection coefficient (Γ) and VSWR(S)

The reflection coefficient (Γ) is given by the formula:

Γ = (Z2 - Z1) / (Z2 + Z1)

Where Z1 and Z2 are the impedances of the two media. The impedance (Z) of a medium is given by the formula:

Z = sqrt(µ/ε)

For the lossless medium, we have:

Z1 = sqrt((5µ0)/(ε0))

For the lossy medium, we have:

Z2 = sqrt((µ0)/(4ε0) - jσ/ω)

Substituting these values into the formula for Γ, we can calculate the reflection coefficient.

The Voltage Standing Wave Ratio (VSWR or S) is given by the formula:

S = (1 + |Γ|) / (1 - |Γ|)

Substituting the value of Γ we calculated earlier, we can find the VSWR.

ii) Total electric and magnetic field intensity(E,H)

The total electric field intensity (E) is the sum of the incident and reflected electric fields. The incident electric field is given in the problem, and the reflected electric field can be found by multiplying the incident field by the reflection coefficient (Γ).

The magnetic field intensity (H) can be found using the formula:

H = E / Z

For both the incident and reflected waves, we can calculate H using the respective values of E and Z.

Please note that this is a simplified explanation and the actual calculations may involve complex numbers due to the presence of the lossy medium.

This problem has been solved

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