A plane electromagnetic wave travels in a medium of relative permeability 1.6 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5 × 10–2 A m–1 at a point, what will be the approximate magnitude of electric field intensity at that point? (Given: permeability of free space  μ0  =  4π × 10−7​N​A−2, speed of light in vacuum c = 3 × 108 m/s)

he electromagnetic wave travels in a medium at a speed of 2.0 × 108m/s. The relative permeability of the medium is 1.0. The relative permittivity of the medium will be:

In a region of space, an electromagnetic wave moves to the right, as indicated in the above diagram. At one moment, the magnitude of the electric field at the indicated point is |𝐸→|=2991 N/C, and its direction is out of the page. In the following questions, use 𝑐=3×108 𝑚/𝑠.A. At this point and time, what is the magnitude of the associated magnetic field? 0 𝑇

If E and B represent electric and magnetic field vectors of the electromagnetic waves respectively, then the direction and magnitude of propagation of the electromagnetic wave is given as ......*1 pointE.HH.E(E x B)/μ0B x H

For a plane travelling EM wave. the correct equation for characteristic impedance Z for the medium with permittivity of ε and permeability of µ isa) Z = b) Z = c) Z = d) Z = 1 /

he refractive index and permeability of a medium are 1.51.5 and 5×10−7 H m−15×10-7 H m-1 respectively. The relative permittivity of the medium is nearly