Understanding Arithmetic operatorsWhat will be the output of the code given below?#include <stdio.h>int main() { int i = 3; int a = i / -2; int k = i % -2; printf("%d %d\n", a, k); return 0;}Options-1 11 -1Compile time error1 1

The output of the given code will be -1 1.

Here's the step by step explanation:

1. The variable 'i' is initialized with the value 3.

2. The variable 'a' is assigned the value of 'i' divided by -2. In C, when you divide a positive number by a negative number, the result is always rounded towards zero. So, 3 divided by -2 equals -1.5, but since we are dealing with integers, the decimal part is discarded and 'a' becomes -1.

3. The variable 'k' is assigned the value of 'i' modulo -2. The modulo operation finds the remainder after division of one number by another. In this case, 3 modulo -2 equals 1, because when 3 is divided by 2, the remainder is 1.

4. The printf function then prints the values of 'a' and 'k', which are -1 and 1 respectively.