Understanding Arithmetic operatorsWhat will be the output of the code given below .#include <stdio.h>int main() { int i = 3; int a = i / -2; int k = i % -2; printf("%d %d\n", a, k); return 0;}

The code is written in C language and it is using arithmetic operators.

The variable 'i' is initialized with the value 3.

Then, the variable 'a' is assigned the value of 'i' divided by -2. In C, when you divide an integer by another integer, the result is also an integer. So, 3 divided by -2 equals -1.5, but since we are dealing with integers, the decimal part is truncated and the result is -1.

Next, the variable 'k' is assigned the value of 'i' modulo -2. The modulo operation finds the remainder after division of one number by another. So, 3 modulo -2 equals 1.

Finally, the printf function is used to print the values of 'a' and 'k', which are -1 and 1 respectively.

So, the output of the code will be: -1 1