The relation between the angle of rotation (θ) in radians and time (t) in secondsof a rotating body is given by the equation. θ = 2t3 + 3t2 + 10. Interpret the angularvelocity after 4 seconds.
Question
The relation between the angle of rotation (θ) in radians and time (t) in secondsof a rotating body is given by the equation. θ = 2t3 + 3t2 + 10. Interpret the angularvelocity after 4 seconds.
Solution
The angular velocity of a rotating body is given by the derivative of the angle of rotation with respect to time.
Given the equation θ = 2t³ + 3t² + 10, we can find the angular velocity by taking the derivative of this equation with respect to time (t).
The derivative of 2t³ with respect to t is 6t². The derivative of 3t² with respect to t is 6t. The derivative of 10 with respect to t is 0.
So, the angular velocity (ω) is given by the equation ω = 6t² + 6t.
To find the angular velocity after 4 seconds, we substitute t = 4 into this equation:
ω = 6(4)² + 6(4) = 96 + 24 = 120 rad/s.
So, the angular velocity of the rotating body after 4 seconds is 120 rad/s.
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