The angular velocity of a particle is given by ω = 1.5 t – 3t2 + 2, the time when its angular acceleration becomes zero
Question
The angular velocity of a particle is given by ω = 1.5 t – 3t2 + 2, the time when its angular acceleration becomes zero
Solution
To find the time when the angular acceleration becomes zero, we need to determine the value of t that makes the derivative of the angular velocity equation equal to zero.
First, let's find the derivative of the angular velocity equation with respect to time (t):
dω/dt = 1.5 - 6t
Next, we set the derivative equal to zero and solve for t:
1.5 - 6t = 0
Adding 6t to both sides:
6t = 1.5
Dividing both sides by 6:
t = 1.5/6
Simplifying:
t = 0.25
Therefore, the time when the angular acceleration becomes zero is t = 0.25.
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