A boy throws a stone vertically up to a man standing 2.0 m above the boy. lf thestone is thrown up with a velocity of 7.0 m/s, what is the velocity of the stone at theinstant when it is caught by the man? The acceleration due to free fall is '10 m/s2.
Question
A boy throws a stone vertically up to a man standing 2.0 m above the boy. lf thestone is thrown up with a velocity of 7.0 m/s, what is the velocity of the stone at theinstant when it is caught by the man? The acceleration due to free fall is '10 m/s2.
Solution
To solve this problem, we can use the equation of motion:
v² = u² + 2as
where: v is the final velocity (which we want to find), u is the initial velocity (7.0 m/s in this case), a is the acceleration (which is -10 m/s² because it's against the direction of motion), s is the distance (2.0 m in this case).
Substituting the given values into the equation, we get:
v² = (7.0 m/s)² + 2*(-10 m/s²)*(2.0 m)
Solving this equation will give us the final velocity of the stone when it is caught by the man.
Similar Questions
A hiker throws a stone from the upper edge of a vertical cliff. The stone's initial velocity is 25.0 m/s directed at 40.0° with the face of the cliff, as shown in the figure.The stone hits the ground 3.75 s after being thrown.How fast is the stone moving just before it hits the ground?Ignore air friction and express your answer in m/s.
A 5 kg stone is dropped from a height of 2 m. What is the speed of the stone when it hits the floor? Consider g = 10 ms-2Question 7Select one:a.6.3 m/sb.10 m/sc.2 m/sd.12.6 m/se.5 m/s
A stone is projected horizontally with a velocity of 10m/s from the top of a building 39.2 m high. How long will the stone take to hit the ground.
A 95 kg man standing on a surface of negligible friction shoves a 74 g stone lying at his feet, giving it a velocity of 4.0 m/s. What velocity does the man acquire as a result?
A stone is released from the top of a tower of height 980 m. Calculate its velocity after 3 seconds. (Take g = 9.8 m/s2)
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.