A 5 kg stone is dropped from a height of 2 m. What is the speed of the stone when it hits the floor? Consider g = 10 ms-2Question 7Select one:a.6.3 m/sb.10 m/sc.2 m/sd.12.6 m/se.5 m/s
Question
A 5 kg stone is dropped from a height of 2 m. What is the speed of the stone when it hits the floor? Consider g = 10 ms-2Question 7Select one:a.6.3 m/sb.10 m/sc.2 m/sd.12.6 m/se.5 m/s
Solution
To solve this problem, we can use the equation of motion that relates final velocity, initial velocity, acceleration and distance. The equation is:
v² = u² + 2gs
where: v is the final velocity (which we are trying to find), u is the initial velocity (since the stone is dropped, u = 0), g is the acceleration due to gravity (given as 10 m/s²), and s is the distance (given as 2 m).
Substituting the given values into the equation, we get:
v² = 0 + 2102 v² = 40 v = sqrt(40) v = 6.3 m/s
So, the speed of the stone when it hits the floor is approximately 6.3 m/s. Therefore, the correct answer is a. 6.3 m/s.
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