The torque (τ) on an object is calculated by the equation τ = rFsinθ, where r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the force is applied perpendicular to the door, so θ = 90 degrees. The sine of 90 degrees is 1, so the equation simplifies to τ = rF.

The force (F) is given as 83 N and the distance (r) is given as 72 cm, but we need to convert this to meters to match the units of the force. So, r = 72 cm = 0.72 m.

Substituting these values into the equation gives:

τ = (0.72 m)(83 N) = 59.76 N*m

Rounding to two significant figures gives a torque of 60 N*m.

Question

The torque (τ) on an object is calculated by the equation τ = rFsinθ, where r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the force is applied perpendicular to the door, so θ = 90 degrees. The sine of 90 degrees is 1, so the equation simplifies to τ = rF.

The force (F) is given as 83 N and the distance (r) is given as 72 cm, but we need to convert this to meters to match the units of the force. So, r = 72 cm = 0.72 m.

Substituting these values into the equation gives:

τ = (0.72 m)(83 N) = 59.76 N*m

Rounding to two significant figures gives a torque of 60 N*m.

Knowee AI · Accepted Answer

The torque (τ) on an object is calculated by the equation τ = rFsinθ, where r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the force is applied perpendicular to the door, so θ = 90 degrees. The sine of 90 degrees is 1, so the equation simplifies to τ = rF.

The force (F) is given as 83 N and the distance (r) is given as 72 cm, but we need to convert this to meters to match the units of the force. So, r = 72 cm = 0.72 m.

Substituting these values into the equation gives:

τ = (0.72 m)(83 N) = 59.76 N*m

Rounding to two significant figures gives a torque of 60 N*m.

A person exerts a horizontal force of 83 NN on the end of a door 72 cmcm wide.Part AWhat is the magnitude of the torque if the force is exerted perpendicular to the door?Express your answer using two significant figure

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