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Find the torque applied to a doorknob if a person applies a force of 18 N 80° from the axis of rotation, at a distance of 2.0 cm from the doorknob. use grade 12 knowledge

Question

Find the torque applied to a doorknob if a person applies a force of 18 N 80° from the axis of rotation, at a distance of 2.0 cm from the doorknob. use grade 12 knowledge

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Solution

Sure, to find the torque, we can use the formula:

Torque = Force x Distance x sin(θ)

where:

  • Force is the force applied, which is 18 N.
  • Distance is the distance from the axis of rotation, which is 2.0 cm or 0.02 m (since we need to convert cm to m for the SI unit consistency).
  • θ is the angle between the force and the position vector, which is 80°.

Let's plug the values into the formula:

Torque = 18 N x 0.02 m x sin(80°)

First, calculate the sine of 80 degrees. Using a calculator, sin(80°) is approximately 0.9848.

So, Torque = 18 N x 0.02 m x 0.9848

Now, multiply these values together:

Torque = 0.353728 N.m

So, the torque applied to the doorknob is approximately 0.354 N.m.

This problem has been solved

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