If the Math Olympiad Club consists of 14 students, how many different teams of 6 students can be formed for competitions?
Question
If the Math Olympiad Club consists of 14 students, how many different teams of 6 students can be formed for competitions?
Solution
To solve this problem, we need to use the concept of combinations in mathematics. A combination is a selection of items without considering the order.
The formula for combinations is:
C(n, k) = n! / [k!(n-k)!]
where:
- n is the total number of items,
- k is the number of items to choose,
- "!" denotes factorial, which means multiplying all positive integers up to that number.
In this case, n = 14 (the total number of students) and k = 6 (the number of students in a team).
So, we can substitute these values into the formula:
C(14, 6) = 14! / [6!(14-6)!]
Calculating the factorials:
14! = 14 × 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 6! = 6 × 5 × 4 × 3 × 2 × 1 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1
Substituting these values back into the formula:
C(14, 6) = 14! / [6! × 8!]
After calculating the above expression, we find that there are 3003 different teams of 6 students that can be formed from a club of 14 students.
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