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If two liquids A (PºA =100 torr) and B (PºB = 200 torr) are completely immiscible with eachother, each one will behave independently of the other, are present in a closed vessel. The totalvapour pressure of the system will be:

Question

If two liquids A (PºA =100 torr) and B (PºB = 200 torr) are completely immiscible with eachother, each one will behave independently of the other, are present in a closed vessel. The totalvapour pressure of the system will be:

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Solution

To find the total vapor pressure of the system, we need to consider the vapor pressures of the individual liquids A and B. Since the liquids are completely immiscible, they do not mix or interact with each other.

The vapor pressure of liquid A is given as PºA = 100 torr, and the vapor pressure of liquid B is given as PºB = 200 torr.

In this case, each liquid will behave independently and contribute its own vapor pressure to the total vapor pressure of the system. Therefore, the total vapor pressure of the system will be the sum of the vapor pressures of A and B.

Total vapor pressure = PºA + PºB Total vapor pressure = 100 torr + 200 torr Total vapor pressure = 300 torr

So, the total vapor pressure of the system will be 300 torr.

This problem has been solved

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