A container filled with a sample of an ideal gas at the pressure of 1.5 atm. The gas is compressed isothermally to one-fourth of its original volume. What is the new pressure of the gas?
Question
A container filled with a sample of an ideal gas at the pressure of 1.5 atm. The gas is compressed isothermally to one-fourth of its original volume. What is the new pressure of the gas?
Solution
The problem can be solved using the ideal gas law, which states that the pressure of a gas times its volume is constant at a constant temperature (isothermally). This can be written as:
P1 * V1 = P2 * V2
Where: P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume
From the problem, we know that: P1 = 1.5 atm V1 = 1 (we can assume any value for the initial volume, it won't affect the final result) V2 = 1/4 * V1 = 1/4
We can substitute these values into the ideal gas law equation to find P2:
1.5 atm * 1 = P2 * 1/4
Solving for P2 gives:
P2 = 1.5 atm * 4 = 6 atm
So, the new pressure of the gas after it is compressed isothermally to one-fourth of its original volume is 6 atm.
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