In an isothermal process, a mass of gas has its volume reduced from 50 cm3 to 32 cm3. If the initial pressure of the gas is 80 kPa, determine its final pressure.a.125 Pab.125kPac.1.25kPad.12.5kPaClear my choice
Question
In an isothermal process, a mass of gas has its volume reduced from 50 cm3 to 32 cm3. If the initial pressure of the gas is 80 kPa, determine its final pressure.a.125 Pab.125kPac.1.25kPad.12.5kPaClear my choice
Solution
In an isothermal process, the pressure and volume of a gas are inversely proportional. This relationship is described by Boyle's Law, which states that the product of the pressure and volume of a gas is constant if the temperature and amount of gas are held constant. Mathematically, this is expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given in the problem: P1 = 80 kPa V1 = 50 cm3 V2 = 32 cm3
We are asked to find P2.
Substituting the given values into Boyle's Law gives us:
80 kPa * 50 cm3 = P2 * 32 cm3
Solving for P2 gives us:
P2 = (80 kPa * 50 cm3) / 32 cm3 = 125 kPa
So, the final pressure of the gas is 125 kPa. The correct answer is b. 125 kPa.
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