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Calculate the concentration of citric acid (triprotic!) in lime juice using the following titration data.Acid base reaction:  C6H8O7(aq)  +  3 NaOH(aq)  →  C6H5O73-(aq)  + 3 Na+(aq)  +  3 H2O(l)Standard [NaOH]:  0.432 mol L-1Volume sample analysed:  10.00 mLAverage NaOH titration volume:   16.05 mLMolar mass Citric acid: 192.14 g mol-1Calculate your answer to 3 significant figures in units of g/L. Do Not include any units, just your numerical value.The citric acid content of limes is marginally less than that of lemons.

Question

Calculate the concentration of citric acid (triprotic!) in lime juice using the following titration data.Acid base reaction:  C6H8O7(aq)  +  3 NaOH(aq)  →  C6H5O73-(aq)  + 3 Na+(aq)  +  3 H2O(l)Standard [NaOH]:  0.432 mol L-1Volume sample analysed:  10.00 mLAverage NaOH titration volume:   16.05 mLMolar mass Citric acid: 192.14 g mol-1Calculate your answer to 3 significant figures in units of g/L. Do Not include any units, just your numerical value.The citric acid content of limes is marginally less than that of lemons.

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Solution

First, we need to calculate the moles of NaOH used in the titration. We can do this using the formula:

Moles = Concentration x Volume

The concentration of NaOH is given as 0.432 mol/L and the volume used is 16.05 mL, which needs to be converted to liters (0.01605 L). So,

Moles of NaOH = 0.432 mol/L x 0.01605 L = 0.00693 mol

Since the reaction between citric acid and NaOH is in a 1:3 ratio, the moles of citric acid will be one third of the moles of NaOH. So,

Moles of citric acid = 0.00693 mol / 3 = 0.00231 mol

Next, we need to calculate the concentration of citric acid in the lime juice. The volume of the lime juice sample is given as 10.00 mL, which needs to be converted to liters (0.01 L). So,

Concentration = Moles / Volume

Concentration of citric acid = 0.00231 mol / 0.01 L = 0.231 mol/L

Finally, we need to convert this concentration to g/L. We can do this using the molar mass of citric acid, which is given as 192.14 g/mol. So,

Concentration in g/L = Concentration in mol/L x Molar mass

Concentration in g/L = 0.231 mol/L x 192.14 g/mol = 44.4 g/L

So, the concentration of citric acid in the lime juice is 44.4 g/L.

This problem has been solved

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