What will be the output of the following Python code?x = ('count',)m = 2for k in range(int(m)):  x = (x,)  print(x)OptionsError, tuples are immutable((‘count’,)’count’,)(('count',)’count’,)((('count',)’count’,)’count’,)(('count',),)((('count',),),)

What will be the output of the following Python code?s = [[m, m + 1, m + 2] for m in range(0, 3)]print(s)Options[0, 1, 2, 1, 2, 3, 2, 3, 4][[0, 1, 2], [1, 2, 3], [2, 3, 4]][[1, 2, 3], [4, 5, 6], [7, 8, 9]][1, 2, 3, 4, 5, 6, 7, 8, 9]

What will be the output of the following Python code?>>> z=(5,6,7,8)>>> del(z[2])OptionsError as tuple is immutableNow, z=(5,7,8)Now, z=(5,6,8)Now z=(7,8)

What will be the output of the following Python code?a1={3, 4}a2={1, 2}a3=set()j=0k=0for j in a1:    for k in a2:        a3.add((j,k))        j+=1        k+=1print(a3)Options{(3, 4), (1, 2)}{(4, 2), (3, 1), (4, 1), (5, 2)}{(3, 1), (4, 2)}Error

What will be the output of the following program ?tuple = {} tuple[(1,2,4)] = 8 tuple[(4,2,1)] = 10 tuple[(1,2)] = 12 _sum = 0 for k in tuple: _sum += tuple[k] print(len(tuple) + _sum)

What will be the output of the following Python code?ct = [[1, 7, 3, 2],       [1, 4, 0, 4],       [1, 9, 0, 5],       [1, 3, 2, 7]]for x in range(0, 4):    print(ct[x][3], end = " ")Options2 4 5 71 9 0 51 7 3 21 3 2 7