Sure, here is a step-by-step solution in Python:

1. First, we need to define a function that takes three parameters: the length of the array (n), the array itself (arr), and the divisor (k).

```python
def count_pairs(n, arr, k):
```

2. Initialize a counter to 0. This will keep track of the number of pairs we find.

```python
count = 0
```

3. Loop through the array. For each element, check if the sum of it and the next element is divisible by k. If it is, increment the counter. Be careful not to go out of bounds by stopping the loop at the second last element.

```python
for i in range(n-1):
if (arr[i] + arr[i+1]) % k == 0:
count += 1
```

4. After the loop, check if the counter is still 0. If it is, return "No pairs found". Otherwise, return the count.

```python
if count == 0:
return "No pairs found"
else:
return "Number of pairs: " + str(count)
```

5. Now you can call this function with the inputs. For example

Question

Sure, here is a step-by-step solution in Python:

1. First, we need to define a function that takes three parameters: the length of the array (n), the array itself (arr), and the divisor (k).

```python
def count_pairs(n, arr, k):
```

2. Initialize a counter to 0. This will keep track of the number of pairs we find.

```python
    count = 0
```

3. Loop through the array. For each element, check if the sum of it and the next element is divisible by k. If it is, increment the counter. Be careful not to go out of bounds by stopping the loop at the second last element.

```python
    for i in range(n-1):
        if (arr[i] + arr[i+1]) % k == 0:
            count += 1
```

4. After the loop, check if the counter is still 0. If it is, return "No pairs found". Otherwise, return the count.

```python
    if count == 0:
        return "No pairs found"
    else:
        return "Number of pairs: " + str(count)
```

5. Now you can call this function with the inputs. For example

Knowee AI · Accepted Answer