To integrate the expression, we can follow these steps:

Step 1: Simplify the expression inside the power function.
- The expression inside the power function is $40 \cdot 2x + 5 \cdot 41$.
- Simplifying this expression, we get $80x + 205$.

Step 2: Integrate the simplified expression.
- The integral of $80x + 205$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$, where $C$ is the constant of integration.

Therefore, the integral of $x^{80 \cdot 2x + 5 \cdot 41}$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$.

Question

To integrate the expression, we can follow these steps:

Step 1: Simplify the expression inside the power function.
   - The expression inside the power function is $40 \cdot 2x + 5 \cdot 41$.
   - Simplifying this expression, we get $80x + 205$.

Step 2: Integrate the simplified expression.
   - The integral of $80x + 205$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$, where $C$ is the constant of integration.

Therefore, the integral of $x^{80 \cdot 2x + 5 \cdot 41}$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$.

Knowee AI · Accepted Answer

To integrate the expression, we can follow these steps:

Step 1: Simplify the expression inside the power function.
   - The expression inside the power function is $40 \cdot 2x + 5 \cdot 41$.
   - Simplifying this expression, we get $80x + 205$.

Step 2: Integrate the simplified expression.
   - The integral of $80x + 205$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$, where $C$ is the constant of integration.

Therefore, the integral of $x^{80 \cdot 2x + 5 \cdot 41}$ with respect to $x$ is $\frac{80}{2}x^2 + 205x + C$.

Integrate[xPower[\(40)2x+5\(41),8],x]

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