Calculate the mass in grams of 26.6mol of copper(Ⅰ) chromate. Be sure your answer has the correct number of significant figures.

To calculate the mass in grams of 26.6 mol of copper(I) chromate, we first need to determine the molar mass of copper(I) chromate.

1. Determine the molar mass of copper(I) chromate (Cu2CrO4):

   • Copper (Cu) has a molar mass of 63.55 g/mol. Since there are two copper atoms in copper(I) chromate, the total mass contributed by copper is 63.55 g/mol * 2 = 127.1 g/mol.
   • Chromium (Cr) has a molar mass of 52.00 g/mol. Since there is one chromium atom in copper(I) chromate, the total mass contributed by chromium is 52.00 g/mol * 1 = 52.00 g/mol.
   • Oxygen (O) has a molar mass of 16.00 g/mol. Since there are four oxygen atoms in copper(I) chromate, the total mass contributed by oxygen is 16.00 g/mol * 4 = 64.00 g/mol.
   • Adding these together, the molar mass of copper(I) chromate is 127.1 g/mol + 52.00 g/mol + 64.00 g/mol = 243.1 g/mol.

2. Now that we know the molar mass of copper(I) chromate, we can calculate the mass of 26.6 mol:

   • Mass = number of moles * molar mass
   • Mass = 26.6 mol * 243.1 g/mol = 6466.46 g

However, we need to consider the significant figures in our final answer. The least number of significant figures in the question is three (in the value 26.6 mol), so our final answer should also have three significant figures.

Therefore, the mass of 26.6 mol of copper(I) chromate is 6470 g (rounded to three significant figures).