Calculate the mass in grams of 32.8mol of chromium(Ⅲ) sulfate decahydrate. Be sure your answer has the correct number of significant figures.

To calculate the mass in grams of 32.8 mol of chromium(III) sulfate decahydrate, we first need to determine the molar mass of chromium(III) sulfate decahydrate.

The formula for chromium(III) sulfate decahydrate is Cr2(SO4)3.10H2O.

The molar mass of chromium (Cr) is approximately 52.00 g/mol. The molar mass of sulfur (S) is approximately 32.07 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol. The molar mass of hydrogen (H) is approximately 1.01 g/mol.

So, the molar mass of chromium(III) sulfate decahydrate is:

(2 * 52.00 g/mol) + (3 * (32.07 g/mol + 4 * 16.00 g/mol)) + (10 * (2 * 1.01 g/mol + 16.00 g/mol)) = 392.14 g/mol.

Now, we can calculate the mass in grams of 32.8 mol of chromium(III) sulfate decahydrate:

32.8 mol * 392.14 g/mol = 12866.152 g.

So, the mass of 32.8 mol of chromium(III) sulfate decahydrate is approximately 12866.152 g.