A rectangular piece of paper measures 17 cm by 8 cm. It is folded so that a right angle is formed between the twosegments of the original bottom edge, as shown. What is the area of the new figure?
Question
A rectangular piece of paper measures 17 cm by 8 cm. It is folded so that a right angle is formed between the twosegments of the original bottom edge, as shown. What is the area of the new figure?
Solution
The area of the new figure will be the sum of the areas of the two rectangles formed after folding the paper.
The original rectangle has dimensions 17 cm by 8 cm. When it is folded, one rectangle retains the original length of 17 cm, but its width is now half of the original width, which is 8/2 = 4 cm.
The area of this rectangle is length x width = 17 cm x 4 cm = 68 square cm.
The other rectangle formed has the original width of 8 cm, but its length is now the original length minus the width, which is 17 cm - 8 cm = 9 cm.
The area of this rectangle is length x width = 9 cm x 8 cm = 72 square cm.
So, the total area of the new figure is the sum of the areas of these two rectangles, which is 68 square cm + 72 square cm = 140 square cm.
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