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A rectangular paperboard measuring 25in long and 16in wide has a semicircle cut out of it, as shown below.Find the area of the paperboard that remains. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.16in25in

Question

A rectangular paperboard measuring 25in long and 16in wide has a semicircle cut out of it, as shown below.Find the area of the paperboard that remains. Use the value 3.14 for π, and do not round your answer. Be sure to include the correct unit in your answer.16in25in

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Solution

To find the area of the paperboard that remains, we first need to find the total area of the paperboard and then subtract the area of the semicircle that was cut out.

Step 1: Find the total area of the paperboard The area of a rectangle is given by the formula length x width. So, the total area of the paperboard is 25in x 16in = 400 square inches.

Step 2: Find the area of the semicircle The diameter of the semicircle is the same as the width of the paperboard, which is 16in. Therefore, the radius of the semicircle is 16in/2 = 8in. The area of a circle is given by the formula πr². Since we only have a semicircle (half a circle), the area is (πr²)/2. Substituting the value of r and π, we get (3.14 x (8in)²)/2 = 100.48 square inches.

Step 3: Subtract the area of the semicircle from the total area of the paperboard The area of the paperboard that remains is 400 square inches - 100.48 square inches = 299.52 square inches.

So, the area of the paperboard that remains is 299.52 square inches.

This problem has been solved

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