In a population of 200 mice, 168 mice are black, and 32 mice are white. 96 of the black mice are heterozygous for the color trait. What is the frequency of the black allele in the population? (Assume simple dominance/recessiveness of a single gene with two alleles for the fur color trait.)Multiple Choice0.360.60.70.84
Question
In a population of 200 mice, 168 mice are black, and 32 mice are white. 96 of the black mice are heterozygous for the color trait. What is the frequency of the black allele in the population? (Assume simple dominance/recessiveness of a single gene with two alleles for the fur color trait.)Multiple Choice0.360.60.70.84
Solution
To solve this problem, we need to first understand that in a population, the total number of alleles is twice the number of individuals (since each individual has two alleles).
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Calculate the total number of alleles in the population: 200 mice * 2 alleles/mouse = 400 alleles
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Determine the number of black alleles. The black mice can be either homozygous (BB) or heterozygous (Bb) for the black allele.
- There are 96 heterozygous black mice, so they contribute 96 black alleles (B) and 96 white alleles (b).
- The remaining black mice (168 total black mice - 96 heterozygous black mice = 72 mice) are homozygous, so they contribute 144 black alleles (72 mice * 2 alleles/mouse).
- The white mice are homozygous for the white allele (bb), so they do not contribute any black alleles.
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Add up the black alleles: 96 (from heterozygous black mice) + 144 (from homozygous black mice) = 240 black alleles
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Calculate the frequency of the black allele: 240 black alleles / 400 total alleles = 0.60
So, the frequency of the black allele in the population is 0.60.
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