In a population of birds, the frequency of the recessive allele for feather coloration (a) is 0.25. Assuming the population is in Hardy-Weinberg equilibrium, calculate the following: The frequency of individuals heterozygous for the genotype (Aa).a.0.375b.0.5625c.0.0625d.0.9375
Question
In a population of birds, the frequency of the recessive allele for feather coloration (a) is 0.25. Assuming the population is in Hardy-Weinberg equilibrium, calculate the following: The frequency of individuals heterozygous for the genotype (Aa).a.0.375b.0.5625c.0.0625d.0.9375
Solution
The Hardy-Weinberg equilibrium principle states that in a large, random-mating population, the allele and genotype frequencies will remain constant from generation to generation unless acted upon by outside forces. The principle is often expressed using the equation p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele (A), q is the frequency of the recessive allele (a), and 2pq represents the frequency of heterozygous individuals (Aa).
Given that the frequency of the recessive allele (q) is 0.25, we can calculate the frequency of the dominant allele (p) as 1 - q = 1 - 0.25 = 0.75.
The frequency of individuals heterozygous for the genotype (Aa) is represented by 2pq. Substituting the values we have for p and q, we get 2 * 0.75 * 0.25 = 0.375.
So, the frequency of individuals heterozygous for the genotype (Aa) is 0.375, which corresponds to option a.
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