What is the ratio of mass percentages of C and Cl in C6H12Cl2? (C-12, H-1, and Cl-35.5) A) 6:2 B) 6:1 C) 1:3 D) 1:6 E) 1:1

First, we need to calculate the molar mass of the compound C6H12Cl2.

The molar mass of Carbon (C) is 12 g/mol, Hydrogen (H) is 1 g/mol, and Chlorine (Cl) is 35.5 g/mol.

For C6H12Cl2, the molar mass would be (612) for Carbon + (121) for Hydrogen + (2*35.5) for Chlorine = 72 + 12 + 71 = 155 g/mol.

Next, we calculate the mass percentage of Carbon and Chlorine in the compound.

The mass percentage of Carbon (C) = (mass of C / molar mass of compound) * 100 = (72 / 155) * 100 = 46.45%

The mass percentage of Chlorine (Cl) = (mass of Cl / molar mass of compound) * 100 = (71 / 155) * 100 = 45.81%

Finally, we find the ratio of the mass percentages of Carbon to Chlorine.

The ratio of C to Cl = 46.45 : 45.81

This ratio is approximately 1:1, so the answer is E) 1:1.