4. What is the percent composition of each element in C12H22O11?

To find the percent composition of each element in C12H22O11 (sucrose), you need to know the molar mass of each element and the molar mass of the compound.

1. Find the molar mass of each element:

   • Carbon (C): 12.01 g/mol
   • Hydrogen (H): 1.01 g/mol
   • Oxygen (O): 16.00 g/mol

2. Calculate the molar mass of the compound:

   • C12H22O11: (1212.01 g/mol) + (221.01 g/mol) + (11*16.00 g/mol) = 342.30 g/mol

3. Calculate the percent composition of each element:

   • Carbon: (12*12.01 g/mol) / 342.30 g/mol * 100% = 42.11%
   • Hydrogen: (22*1.01 g/mol) / 342.30 g/mol * 100% = 6.48%
   • Oxygen: (11*16.00 g/mol) / 342.30 g/mol * 100% = 51.41%

So, the percent composition of C12H22O11 is approximately 42.11% Carbon, 6.48% Hydrogen, and 51.41% Oxygen.