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A limb with mass 14 kg falls out of a tree from a height of 3.5 m. How much mechanical energy does the limb have just before it hits the ground? (Assume there is no air resistance.)A.355.3 JB.480.2 JC.49 JD.0 JSUBMITarrow_backPREVIOUS

Question

A limb with mass 14 kg falls out of a tree from a height of 3.5 m. How much mechanical energy does the limb have just before it hits the ground? (Assume there is no air resistance.)A.355.3 JB.480.2 JC.49 JD.0 JSUBMITarrow_backPREVIOUS

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Solution

The mechanical energy of the limb just before it hits the ground is equal to its potential energy at the top of the tree, as energy is conserved (assuming no air resistance).

Potential energy (PE) can be calculated using the formula PE = mgh, where:

  • m is the mass of the object (14 kg in this case),
  • g is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and
  • h is the height from which the object falls (3.5 m in this case).

Substituting these values into the formula gives:

PE = 14 kg * 9.8 m/s² * 3.5 m = 480.2 J

So, the limb has 480.2 Joules of mechanical energy just before it hits the ground. Therefore, the correct answer is B.480.2 J.

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