The expansion of (2x – 3)³ can be found using the binomial theorem, which states that (a - b)³ = a³ - 3a²b + 3ab² - b³.

Here, a = 2x and b = 3.

Step 1: Calculate a³ = (2x)³ = 8x³.
Step 2: Calculate 3a²b = 3*(2x)²*3 = 3*4x²*3 = 36x².
Step 3: Calculate 3ab² = 3*2x*3² = 3*2x*9 = 54x.
Step 4: Calculate b³ = 3³ = 27.

Now, substitute these values back into the formula:

(2x - 3)³ = a³ - 3a²b + 3ab² - b³ = 8x³ - 36x² + 54x - 27.

Question

The expansion of (2x – 3)³ can be found using the binomial theorem, which states that (a - b)³ = a³ - 3a²b + 3ab² - b³.

Here, a = 2x and b = 3.

Step 1: Calculate a³ = (2x)³ = 8x³.
Step 2: Calculate 3a²b = 3*(2x)²*3 = 3*4x²*3 = 36x².
Step 3: Calculate 3ab² = 3*2x*3² = 3*2x*9 = 54x.
Step 4: Calculate b³ = 3³ = 27.

Now, substitute these values back into the formula:

(2x - 3)³ = a³ - 3a²b + 3ab² - b³ = 8x³ - 36x² + 54x - 27.

Knowee AI · Accepted Answer

The expansion of (2x – 3)³ can be found using the binomial theorem, which states that (a - b)³ = a³ - 3a²b + 3ab² - b³.

Here, a = 2x and b = 3.

Step 1: Calculate a³ = (2x)³ = 8x³.
Step 2: Calculate 3a²b = 3*(2x)²*3 = 3*4x²*3 = 36x².
Step 3: Calculate 3ab² = 3*2x*3² = 3*2x*9 = 54x.
Step 4: Calculate b³ = 3³ = 27.

Now, substitute these values back into the formula:

(2x - 3)³ = a³ - 3a²b + 3ab² - b³ = 8x³ - 36x² + 54x - 27.

What is the expansion of (2x – 3)3

Question

Solution

Similar Questions

Upgrade your grade with Knowee