The work done by a force on a body is given by the dot product of the force and the displacement of the body. In the case of centripetal force, the force is always directed towards the center of the circle, while the displacement of the body is along the circumference of the circle.

Since the force and displacement are perpendicular to each other, the angle between them is 90 degrees. The work done is given by the formula:

W = F.d.cosθ

where:
W is the work done,
F is the force,
d is the displacement,
and θ is the angle between the force and displacement.

In this case, the angle θ is 90 degrees. The cosine of 90 degrees is 0. Therefore, the work done by the centripetal force on the body as it moves over any distance (including half the circumference of the circle) is zero.

So, the work done by the centripetal force in moving the body over half the circumference of the circle is zero.

Question

The work done by a force on a body is given by the dot product of the force and the displacement of the body. In the case of centripetal force, the force is always directed towards the center of the circle, while the displacement of the body is along the circumference of the circle.

Since the force and displacement are perpendicular to each other, the angle between them is 90 degrees. The work done is given by the formula:

W = F.d.cosθ

where:
W is the work done,
F is the force,
d is the displacement,
and θ is the angle between the force and displacement.

In this case, the angle θ is 90 degrees. The cosine of 90 degrees is 0. Therefore, the work done by the centripetal force on the body as it moves over any distance (including half the circumference of the circle) is zero.

So, the work done by the centripetal force in moving the body over half the circumference of the circle is zero.

Knowee AI · Accepted Answer

The work done by a force on a body is given by the dot product of the force and the displacement of the body. In the case of centripetal force, the force is always directed towards the center of the circle, while the displacement of the body is along the circumference of the circle.

Since the force and displacement are perpendicular to each other, the angle between them is 90 degrees. The work done is given by the formula:

W = F.d.cosθ

where:
W is the work done,
F is the force,
d is the displacement,
and θ is the angle between the force and displacement.

In this case, the angle θ is 90 degrees. The cosine of 90 degrees is 0. Therefore, the work done by the centripetal force on the body as it moves over any distance (including half the circumference of the circle) is zero.

So, the work done by the centripetal force in moving the body over half the circumference of the circle is zero.

A body of mass m is moving in a circle of radius r with a constant speed v. The work doneby the centripetal force in moving the body over half the circumference of the circle is

Question

Solution

Similar Questions

Upgrade your grade with Knowee