A 5 kg block attached to a string of length 5 m is pulled along an arc of a circle byapplying a constant force of 200 N as shown in the figure. Find the work done by theapplied force. [Use sin 530 = 45
Question
A 5 kg block attached to a string of length 5 m is pulled along an arc of a circle byapplying a constant force of 200 N as shown in the figure. Find the work done by theapplied force. [Use sin 530 = 45
Solution
The problem seems to be missing some information, such as the direction of the force and the distance the block is moved. However, assuming the force is applied tangentially to the circle and the block is moved along the arc of the circle, we can use the formula for work done by a force:
Work = Force x Distance x cos(θ)
where θ is the angle between the force and the direction of motion. In this case, if the force is applied tangentially, θ = 0 degrees and cos(0) = 1.
The distance the block is moved along the arc can be calculated using the formula for the length of an arc:
Arc length = r x θ
where r is the radius of the circle and θ is the angle of the arc in radians. If the block is moved along an arc of 53 degrees, this needs to be converted to radians:
53 degrees = 53 x (π/180) = 0.925 radians
So the arc length is:
Arc length = 5 m x 0.925 = 4.625 m
Then the work done by the force is:
Work = 200 N x 4.625 m x 1 = 925 Joules
Please note that the value of sin 53 = 0.8, not 45. The value of sin cannot be greater than 1.
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