When the force of 20 N is inclined at an angle of 60° from the horizontal then the horizontal component and vertical component of force will be:
Question
When the force of 20 N is inclined at an angle of 60° from the horizontal then the horizontal component and vertical component of force will be:
Solution
The horizontal and vertical components of a force can be calculated using trigonometric functions.
Step 1: Identify the given values. The force (F) is 20 N and the angle (θ) is 60°.
Step 2: Calculate the horizontal component (F_x) of the force. The horizontal component of a force is calculated by multiplying the force by the cosine of the angle.
F_x = F * cos(θ) F_x = 20 N * cos(60°) F_x = 20 N * 0.5 F_x = 10 N
Step 3: Calculate the vertical component (F_y) of the force. The vertical component of a force is calculated by multiplying the force by the sine of the angle.
F_y = F * sin(θ) F_y = 20 N * sin(60°) F_y = 20 N * √3/2 F_y = 10√3 N
So, the horizontal component of the force is 10 N and the vertical component of the force is 10√3 N.
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