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What is the equation of the line that passes through ( 2, -2) and the origin?*

Question

What is the equation of the line that passes through ( 2, -2) and the origin?*

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Solution

The equation of a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Find the slope (m) The slope of a line passing through the points (x1, y1) and (x2, y2) is given by (y2 - y1) / (x2 - x1). Here, (x1, y1) is the origin (0, 0), and (x2, y2) is the point (2, -2). So, the slope m = (-2 - 0) / (2 - 0) = -1.

Step 2: Find the y-intercept (b) Since the line passes through the origin, the y-intercept is 0.

So, the equation of the line that passes through (2, -2) and the origin is y = -x + 0, or simply y = -x.

This problem has been solved

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