A ray of light travels with a speed of 2 ×× 10810 8 in a medium `A' and enters into another medium `B' travelling with velocity 2.5 ×× 10810 8 m/s. If absolute refractive index of medium `A' is 1.52. Calculate the refractive index of medium `B' with respect to `A'.(Find answer upto one places of decimal)0.50.20.81
Question
A ray of light travels with a speed of 2 ×× 10810 8 in a medium A' and enters into another medium B' travelling with velocity 2.5 ×× 10810 8 m/s. If absolute refractive index of medium A' is 1.52. Calculate the refractive index of medium B' with respect to `A'.(Find answer upto one places of decimal)0.50.20.81
Solution
The refractive index of medium B with respect to A (nBA) can be calculated using the formula:
nBA = Speed of light in medium A / Speed of light in medium B
Given that the speed of light in medium A is 2 × 10^8 m/s and in medium B is 2.5 × 10^8 m/s, we can substitute these values into the formula:
nBA = (2 × 10^8) / (
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