A light ray in material 1 goes into material 2. The angle of incidence in material 1 is 40.0° and the angle of refraction in material 2 is 31.0°. If the index of refraction of material 1 is 1.60, what is the index of refraction of material 2?Scegli un'alternativa:A.1.41B.1.88C.1.20D.2.00
Question
A light ray in material 1 goes into material 2. The angle of incidence in material 1 is 40.0° and the angle of refraction in material 2 is 31.0°. If the index of refraction of material 1 is 1.60, what is the index of refraction of material 2?Scegli un'alternativa:A.1.41B.1.88C.1.20D.2.00
Solution
Per risolvere questo problema, possiamo utilizzare la legge di Snell, che afferma che l'indice di rifrazione del primo materiale moltiplicato per il seno dell'angolo di incidenza è uguale all'indice di rifrazione del secondo materiale moltiplicato per il seno dell'angolo di rifrazione.
In termini matematici, questa legge può essere espressa come:
n1 * sin(θ1) = n2 * sin(θ2)
Dove: n1 = indice di rifrazione del materiale 1 θ1 = angolo di incidenza nel materiale 1 n2 = indice di rifrazione del materiale 2 (che stiamo cercando di trovare) θ2 = angolo di rifrazione nel materiale 2
Sostituendo i valori dati nel problema, otteniamo:
1.60 * sin(40.0°) = n2 * sin(31.0°)
Risolvendo per n2, otteniamo:
n2 = (1.60 * sin(40.0°)) / sin(31.0°)
Calcolando i valori, otteniamo:
n2 = 1.88
Quindi, l'indice di rifrazione del materiale 2 è 1.88. Quindi, la risposta corretta è B. 1.88.
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