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What is the peak drug Z level attained at steady state if 150 mg is given by IV injection every 8 hr, the half-life of drug Z in patient being 6 hr and volume of distribution = 0.3 L/kg? (NB pt wt =75 Kg).

Question

What is the peak drug Z level attained at steady state if 150 mg is given by IV injection every 8 hr, the half-life of drug Z in patient being 6 hr and volume of distribution = 0.3 L/kg? (NB pt wt =75 Kg).

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Solution

To solve this problem, we need to use the formula for the peak drug level at steady state, which is:

Peak level = Dose / Volume of Distribution

First, we need to calculate the volume of distribution in liters. Given that the volume of distribution is 0.3 L/kg and the patient's weight is 75 kg, we multiply these two values:

Volume of Distribution = 0.3 L/kg * 75 kg = 22.5 L

Next, we need to convert the dose from mg to g, since the volume of distribution is in liters and we want the concentration in g/L. Given that 1 g = 1000 mg, we have:

Dose = 150 mg = 0.15 g

Now we can calculate the peak level:

Peak level = 0.15 g / 22.5 L = 0.00667 g/L

This is the peak drug level attained at steady state.

This problem has been solved

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